#!/usr/bin/python
#
# wrapper for subscription Manager commandline tool.
#
# Copyright (c) 2010 Red Hat, Inc.
#
# Authors: Pradeep Kilambi
#
# This software is licensed to you under the GNU General Public License,
# version 2 (GPLv2). There is NO WARRANTY for this software, express or
# implied, including the implied warranties of MERCHANTABILITY or FITNESS
# FOR A PARTICULAR PURPOSE. You should have received a copy of GPLv2
# along with this software; if not, see
# http://www.gnu.org/licenses/old-licenses/gpl-2.0.txt.
#
# Red Hat trademarks are not licensed under GPLv2. No permission is
# granted to use or replicate Red Hat trademarks that are incorporated
# in this software or its documentation.
#

if __name__ != '__main__':
    raise ImportError("module cannot be imported")

import sys
import os

def systemExit(code, msgs=None):
    "Exit with a code and optional message(s). Saved a few lines of code."

    if msgs:
        if type(msgs) not in [type([]), type(())]:
            msgs = (msgs, )
        for msg in msgs:
            sys.stderr.write(str(msg)+'\n')
    sys.exit(code)


_LIBPATH = "/usr/share/rhsm"
# add to the path if need be
if _LIBPATH not in sys.path:
    sys.path.append(_LIBPATH)

# quick check to see if you are a super-user.
if os.getuid() != 0:
    sys.stderr.write('ERROR: must be root to execute\n')
    sys.exit(8)

try:
    # this has to be done first thing (due to module level translated vars,
    # like in constants.py
    from subscription_manager.managerlib import configure_i18n
    configure_i18n()

    from subscription_manager import managercli
    from subscription_manager.managercli import handle_exception
except KeyboardInterrupt:
    systemExit(0, "\nUser interrupted process.")
except ImportError, e:
    systemExit(2, "Unable to find Subscription Manager module.\n"
                  "Error: %s" % e)


from subscription_manager import logutil
logutil.init_logger()

def main():
    # execute
    try:
        return managercli.CLI().main()
    except KeyboardInterrupt:
        systemExit(0, "\nUser interrupted process.")

    return 0


if __name__ == '__main__':
    try:
        sys.exit(abs(main() or 0))
    except SystemExit, e:
        #this is a non-exceptional exception thrown by Python 2.4, just
        #re-raise, bypassing handle_exception
        raise e
    except KeyboardInterrupt:
        systemExit(0, "\nUser interrupted process.")
    except Exception, e:
        handle_exception("exception caught in subscription-manager", e)
